在java中颠倒整数(关于方法的问题)

public class ReverseInteger {
    public static int reverse(int x) {
        int reversed = 0;
        while (x != 0) {
            int digit = x % 10; // 获取最后一位数字
            x /= 10; // 移除最后一位数字
            reversed = reversed * 10 + digit; // 将最后一位数字添加到反转后的数字中
        }
        return reversed;
    }

    public static void main(String[] args) {
        int number = 12345;
        System.out.println("Original number: " + number);
        System.out.println("Reversed number: " + reverse(number));
    }
}

public static int reverse(int x) {
    long reversed = 0;
    while (x != 0) {
        int digit = x % 10;
        x /= 10;
        reversed = reversed * 10 + digit;
    }
    if (reversed > Integer.MAX_VALUE || reversed < Integer.MIN_VALUE) {
        return 0; // 或者抛出异常
    }
    return (int) reversed;
}