基于两个单独的排名/分组将日期时段分组在一起

from collections import defaultdict
from datetime import datetime

# 假设的数据
data = [
    {"date_time": "2023-04-01T10:00:00", "priority": 1, "department": "A"},
    {"date_time": "2023-04-01T11:00:00", "priority": 2, "department": "A"},
    {"date_time": "2023-04-01T12:00:00", "priority": 1, "department": "B"},
    # 更多数据...
]

# 分组函数
def group_by_rank_and_department(data):
    grouped = defaultdict(lambda: defaultdict(list))
    for entry in data:
        date_time = datetime.fromisoformat(entry["date_time"])
        priority = entry["priority"]
        department = entry["department"]
        grouped[department][priority].append(date_time)
    return grouped

# 执行分组
grouped_data = group_by_rank_and_department(data)

# 输出结果
for department, priorities in grouped_data.items():
    print(f"Department: {department}")
    for priority, times in priorities.items():
        print(f"  Priority {priority}: {times}")