基于满足条件比较版本字符串的最有效的Python化方法

from distutils.version import StrictVersion

def compare_versions(version1, version2):
    v1 = StrictVersion(version1)
    v2 = StrictVersion(version2)
    
    if v1 > v2:
        return f"{version1} is greater than {version2}"
    elif v1 < v2:
        return f"{version1} is less than {version2}"
    else:
        return f"{version1} is equal to {version2}"

# 示例用法
print(compare_versions("1.2.3", "1.2.4"))  # 输出：1.2.3 is less than 1.2.4
print(compare_versions("2.0", "1.9.9"))     # 输出：2.0 is greater than 1.9.9
print(compare_versions("3.0.0", "3.0.0"))   # 输出：3.0.0 is equal to 3.0.0