我正在使用Python从页面中提取链接:
for link in soup.find_all('a', href=True):
if 'http' in link['href']:
links.append(link['href'])
我如何构造一些东西来打开每个链接,并从链接页面上的"p“标记中提取文本?
下面是我的代码
<a href="http://linkurl" class="link" title="sometitle">
text link
<span class="hidden-tooltip-data" style="display: none;"> <a
href="http://www.google.ca"> my link here destroy everything </a
</span>
</a
我被困在这个问题上了。我的项目是做this..This周你将创建一个网站开发公司的主题。
* You can use http://www.1kbgrid.com/ for a base design.
* Come up with a color scheme that will match this logo.
* Decide what your top links should be. Create an RSS feed for these top pages.
* Create a report that states the scope of the project (why
我正在使用作为我的网站。这个编辑器有内置的图像上传功能-图像上传工作良好,但我的反应有困难。
这是从文件中得出的:
The server processes the HTTP request.
The server has to process the upload request, save the image and return a hashmap containing a link to the uploaded image. The returned hashmap needs to look like: { link: 'path_to_uploaded_file/file
我想使用Linq来帮助制作一个演员出演过的电影的列表。我当前正在尝试使用此查询:
XDocument doc = XDocument.Load(reqUrl);
var items = (from c in doc.Descendants("filmography")
select new Actor
{
Filmograpgy = c.Element("link").Value,
我正在尝试使用Dispatcher运行一个简单的Struts示例,但是我得到了以下错误
SEVERE: Servlet.service() for servlet [jsp] in context with path [/StrutsDispatcher] threw
exception [java.lang.NullPointerException: Module 'null' not found.] with root cause
java.lang.NullPointerException: Module 'null' not found.
at org