如何从另一个django应用程序呈现表单，包括错误处理

# forms.py
from django import forms

class MyForm(forms.Form):
    name = forms.CharField(max_length=100)
    email = forms.EmailField()

# views.py
from django.shortcuts import render
from .forms import MyForm

def my_view(request):
    if request.method == 'POST':
        form = MyForm(request.POST)
        if form.is_valid():
            # 处理表单数据
            name = form.cleaned_data['name']
            email = form.cleaned_data['email']
            # 其他逻辑处理
            return render(request, 'success.html')
    else:
        form = MyForm()
    
    return render(request, 'my_form.html', {'form': form})

# urls.py
from django.urls import path
from .views import my_view

urlpatterns = [
    path('my-form/', my_view, name='my-form'),
]

# 在另一个Django应用程序中引用表单
from myapp.forms import MyForm

def another_view(request):
    form = MyForm()
    return render(request, 'another_form.html', {'form': form})