如何从根角垫树中获取节点路径

class TreeNode:
    def __init__(self, val):
        self.val = val
        self.left = None
        self.right = None

def find_path(root, target):
    if not root:
        return []
    
    path = []
    path.append(root.val)
    
    if root.val == target:
        return path
    
    if root.left:
        left_path = find_path(root.left, target)
        if left_path:
            return path + left_path
    
    if root.right:
        right_path = find_path(root.right, target)
        if right_path:
            return path + right_path
    
    path.pop()
    return []

# 示例用法
# 创建一个二叉树
root = TreeNode(1)
root.left = TreeNode(2)
root.right = TreeNode(3)
root.left.left = TreeNode(4)
root.left.right = TreeNode(5)
root.right.left = TreeNode(6)
root.right.right = TreeNode(7)

# 获取节点路径
target = 5
path = find_path(root, target)
print("节点路径:", path)