如何从log4j堆栈跟踪中过滤某些行？

import java.util.regex.Pattern;
import java.util.regex.Matcher;

public class Log4jFilterExample {

    public static void main(String[] args) {
        try {
            // 抛出异常以生成堆栈跟踪
            throw new Exception("Test exception");
        } catch (Exception e) {
            // 获取堆栈跟踪
            StackTraceElement[] stackTrace = e.getStackTrace();

            // 使用正则表达式过滤堆栈跟踪中的某些行
            Pattern pattern = Pattern.compile(".*Log4jFilterExample.*");
            StringBuilder filteredStackTrace = new StringBuilder();
            for (StackTraceElement element : stackTrace) {
                Matcher matcher = pattern.matcher(element.toString());
                if (!matcher.matches()) {
                    filteredStackTrace.append(element.toString()).append("\n");
                }
            }

            // 输出过滤后的堆栈跟踪
            System.out.println(filteredStackTrace.toString());
        }
    }
}