如何使用groovy获得相同键迭代次数的所有JSON值？

使用Groovy可以通过以下步骤获得相同键迭代次数的所有JSON值：

1. 导入所需的Groovy库：@Grab('org.json:json:20210307') import groovy.json.JsonSlurper
2. 定义一个JSON字符串：def jsonStr = '{"key1": "value1", "key2": "value2", "key3": "value3", "key4": "value4", "key5": "value5", "key6": "value6", "key7": "value7", "key8": "value8", "key9": "value9", "key10": "value10", "key11": "value11", "key12": "value12", "key13": "value13", "key14": "value14", "key15": "value15", "key16": "value16", "key17": "value17", "key18": "value18", "key19": "value19", "key20": "value20"}'
3. 解析JSON字符串为Groovy对象：def json = new JsonSlurper().parseText(jsonStr)
4. 创建一个空的Map来存储相同键迭代次数的所有JSON值：def resultMap = [:]
5. 遍历JSON对象的所有键值对，将相同键的值添加到结果Map中：json.each { key, value -> if (resultMap.containsKey(key)) { resultMap[key] << value } else { resultMap[key] = [value] } }
6. 打印结果Map中的所有键值对：resultMap.each { key, values -> println "Key: $key" println "Values: $values" println "-------------------" }

完整的代码示例：

@Grab('org.json:json:20210307')
import groovy.json.JsonSlurper

def jsonStr = '{"key1": "value1", "key2": "value2", "key3": "value3", "key4": "value4", "key5": "value5", "key6": "value6", "key7": "value7", "key8": "value8", "key9": "value9", "key10": "value10", "key11": "value11", "key12": "value12", "key13": "value13", "key14": "value14", "key15": "value15", "key16": "value16", "key17": "value17", "key18": "value18", "key19": "value19", "key20": "value20"}'

def json = new JsonSlurper().parseText(jsonStr)
def resultMap = [:]

json.each { key, value ->
    if (resultMap.containsKey(key)) {
        resultMap[key] << value
    } else {
        resultMap[key] = [value]
    }
}

resultMap.each { key, values ->
    println "Key: $key"
    println "Values: $values"
    println "-------------------"
}

这段代码将输出每个键的所有值，例如：

Key: key1
Values: [value1]
-------------------
Key: key2
Values: [value2]
-------------------
Key: key3
Values: [value3]
-------------------
...

请注意，这只是一个示例代码，你可以根据自己的需求进行修改和扩展。