如何使用java/python从xml结构中获取匹配xpath的DOM结构

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpression;
import javax.xml.xpath.XPathExpressionException;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;

public class XPathExample {
    public static void main(String[] args) {
        try {
            // 创建一个DocumentBuilder对象
            DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
            DocumentBuilder builder = factory.newDocumentBuilder();

            // 解析XML文件，生成一个Document对象
            Document document = builder.parse("path/to/your/xml/file.xml");

            // 创建XPath对象
            XPathFactory xPathFactory = XPathFactory.newInstance();
            XPath xpath = xPathFactory.newXPath();

            // 编译XPath表达式
            XPathExpression expr = xpath.compile("//your/xpath/expression");

            // 在文档中执行XPath表达式，获取匹配的节点列表
            NodeList nodeList = (NodeList) expr.evaluate(document, XPathConstants.NODESET);

            // 遍历匹配的节点列表
            for (int i = 0; i < nodeList.getLength(); i++) {
                // 处理匹配的节点
                // ...
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

import xml.etree.ElementTree as ET

# 解析XML文件，生成一个ElementTree对象
tree = ET.parse('path/to/your/xml/file.xml')

# 创建XPath对象
xpath = ET.XPath("//your/xpath/expression")

# 在文档中执行XPath表达式，获取匹配的节点列表
node_list = xpath(tree)

# 遍历匹配的节点列表
for node in node_list:
    # 处理匹配的节点
    # ...