如何使用javascript删除多参数url？

const url = new URL(window.location.href);

url.searchParams.delete('param1');
url.searchParams.delete('param2');

const newUrl = url.toString();

function removeParamsFromUrl(urlString, paramsToRemove) {
  const url = new URL(urlString);
  
  for (const param of paramsToRemove) {
    url.searchParams.delete(param);
  }

  return url.toString();
}

const url = 'https://www.example.com/page?param1=value1&param2=value2&param3=value3';
const paramsToRemove = ['param1', 'param2'];
const newUrl = removeParamsFromUrl(url, paramsToRemove);

console.log(newUrl);