如何使用python返回未以"\listing“开头的href链接

import re

def get_links(text):
    pattern = r'<a\s+href="([^"]+)"[^>]*>'
    links = re.findall(pattern, text)
    filtered_links = [link for link in links if not link.startswith("\\listing")]
    return filtered_links

# 示例文本
text = '''
<a href="https://www.example.com">Example Link</a>
<a href="https://www.example.com/listing1">Listing 1</a>
<a href="https://www.example.com/listing2">Listing 2</a>
<a href="https://www.example.com/listing3">Listing 3</a>
'''

# 获取未以"\listing"开头的href链接
filtered_links = get_links(text)

# 打印结果
for link in filtered_links:
    print(link)

https://www.example.com