我正在编写一个userscript,其中包含由userscript插件注入的依赖项。我不能导入任何库,我只想要类型。添加TS之前的JS代码是有效的。
示例:
R.range(0, 3)
上的TypeScript编译器崩溃
'R' refers to a UMD global, but the current file is a module. Consider adding an import instead.
我试过了
/// <reference path="../../node_modules/@types/ramda/index.d.ts"/>
在使用webpack &babel为浏览器编译我的应用程序之后,在主函数启动之前就会突然出现以下错误:
Uncaught TypeError: Cannot destructure property `curry` of 'undefined' or 'null'.
at Object../node_modules/@qzdio/f/lib/combinators/sync.js (index-c1596672f4.js:formatted:268)
at n (runtime-74c3f0da77.js:formatted:10)
我注意到,如果我使用ramda,有时在为导出的方法编写Jest测试时会遇到问题。我已经把这个问题写成了下面的测试和两个基本的还原剂函数。我已经在gist上发布了关于不要用代码堵塞这个问题的帖子。
对于ramda减速器,我得到以下错误:
● counter usage › counter counts the words and their index in the given list of words
expect(received).toEqual(expected)
Expected value to equal:
[{"count&
如何以更实用的/声明性的方式编写这段代码?
type FieldType = "dropdown" | "text" | "file" | null;
const getFieldType = (field: {isDropdown?: boolean, isTextInput?: boolean, isFileModal?: boolean}) => {
// a field can have all 3 of the above boolean properties at once as "true"
//but som
使用javascript和typescript中的函数式编程以及Ramda,我经常会编写如下代码:
const myFun = c => {
const myId = c.id
const value = pipe(
getAnotherOtherPropOfC,
transformToArray,
mapToSomething,
filterSomething,
// ... N other transformations
// ok now I need myId and also the result of the prev
我一直在尝试和webpack一起设置angular 1,但是遇到了导入模块的问题,比方说我想从node_modules导入ramda
import angular from 'angular';
import uirouter form 'angular-ui-router';
import routing from './app.config';
import * as ramda from 'ramda';
angular.module('app', [uirouter, ramda])
.config
假设我有以下不纯的功能:
// Mounts a foo instance into the given dom node
// (this is an implementation detail of the Foo library),
// then returns the foo instance.
const createFoo = (FooConstructor, domNode, options) => {
return new FooConstructor(domNode, options);
};
const outlineFoo = foo => {
f