如何在从列表中删除项目时递减order numbers列

# 假设项目列表为一个包含字典的列表，每个字典表示一个项目
projects = [
    {"id": 1, "name": "项目1", "order": 1},
    {"id": 2, "name": "项目2", "order": 2},
    {"id": 3, "name": "项目3", "order": 3},
    {"id": 4, "name": "项目4", "order": 4}
]

# 要删除的项目ID
delete_project_id = 2

# 找到要删除的项目
delete_project = None
for project in projects:
    if project["id"] == delete_project_id:
        delete_project = project
        break

# 如果找到了要删除的项目，则执行删除操作
if delete_project:
    projects.remove(delete_project)
    # 更新后续项目的order numbers值
    for project in projects:
        if project["order"] > delete_project["order"]:
            project["order"] -= 1

# 打印更新后的项目列表
for project in projects:
    print(project)