如何在使用位字段的C中显示结构变量的位模式？

struct MyStruct {
    unsigned int field1 : 5;   // 5位的位字段
    unsigned int field2 : 3;   // 3位的位字段
    unsigned int field3 : 8;   // 8位的位字段
};

struct MyStruct myVar;
myVar.field1 = 7;
myVar.field2 = 3;
myVar.field3 = 255;

unsigned char bytes[sizeof(struct MyStruct)];
memcpy(bytes, &myVar, sizeof(struct MyStruct));

for (int i = 0; i < sizeof(struct MyStruct); i++) {
    for (int j = 7; j >= 0; j--) {
        printf("%d", (bytes[i] >> j) & 1);
    }
    printf(" ");
}

#include <stdio.h>
#include <string.h>

struct MyStruct {
    unsigned int field1 : 5;
    unsigned int field2 : 3;
    unsigned int field3 : 8;
};

int main() {
    struct MyStruct myVar;
    myVar.field1 = 7;
    myVar.field2 = 3;
    myVar.field3 = 255;

    unsigned char bytes[sizeof(struct MyStruct)];
    memcpy(bytes, &myVar, sizeof(struct MyStruct));

    for (int i = 0; i < sizeof(struct MyStruct); i++) {
        for (int j = 7; j >= 0; j--) {
            printf("%d", (bytes[i] >> j) & 1);
        }
        printf(" ");
    }

    return 0;
}