如何在具有“复杂”结构的 php 中使用 json？

<?php
// 创建一个复杂的数据结构
$data = array(
    'name' => 'John',
    'age' => 30,
    'email' => 'john@example.com',
    'address' => array(
        'street' => '123 Main St',
        'city' => 'New York',
        'state' => 'NY'
    ),
    'friends' => array(
        array('name' => 'Jane', 'age' => 28),
        array('name' => 'Bob', 'age' => 32)
    )
);

// 将数据结构转换为JSON字符串
$jsonString = json_encode($data);

// 输出JSON字符串
echo $jsonString;
// 输出结果：{"name":"John","age":30,"email":"john@example.com","address":{"street":"123 Main St","city":"New York","state":"NY"},"friends":[{"name":"Jane","age":28},{"name":"Bob","age":32}]}

// 将JSON字符串转换为PHP数据结构
$decodedData = json_decode($jsonString, true);

// 访问解码后的数据
echo $decodedData['name'];  // 输出结果：John
echo $decodedData['address']['city'];  // 输出结果：New York
echo $decodedData['friends'][0]['name'];  // 输出结果：Jane
?>