如何在导航参数中传递fetch响应？

// 发送fetch请求
fetch('https://api.example.com/data')
  .then(response => response.json())
  .then(data => {
    // 将fetch响应转换为字符串
    const responseData = JSON.stringify(data);

    // 构建导航URL
    const url = new URL('https://example.com/newpage');
    const params = new URLSearchParams();
    params.append('fetchResponse', responseData);
    url.search = params.toString();

    // 导航到新页面
    window.location.href = url.toString();
  });

// 在新页面中提取导航参数并解析fetch响应
const urlParams = new URLSearchParams(window.location.search);
const fetchResponse = urlParams.get('fetchResponse');
const parsedResponse = JSON.parse(fetchResponse);

// 对解析出的响应进行处理
console.log(parsedResponse);