如何在没有外部递归函数的情况下解析多个嵌套的JSON键？

import json

def parse_nested_json(json_data):
    result = {}
    stack = [(None, json_data)]  # 初始根键和值入栈

    while stack:
        key, value = stack.pop()

        if isinstance(value, dict):  # 处理嵌套的JSON对象
            for k, v in value.items():
                stack.append((k, v))
        elif isinstance(value, list):  # 处理嵌套的JSON数组
            for i, item in enumerate(value):
                stack.append((str(i), item))
        else:  # 处理其他值类型
            result[key] = value

    return result

# 示例用法
json_str = '{"name": "John", "age": 30, "address": {"city": "New York", "country": "USA"}, "hobbies": ["reading", "traveling"]}'
json_data = json.loads(json_str)

parsed_data = parse_nested_json(json_data)
print(parsed_data)

{'name': 'John', 'age': 30, 'city': 'New York', 'country': 'USA', '0': 'reading', '1': 'traveling'}