如何在请求URL( Java 11)中添加参数？

String url = "https://www.example.com";
String name = "John";
int age = 25;
String parameter = "?" + "name=" + name + "&age=" + age;
String fullUrl = url + parameter;

import java.net.URI;
import java.net.URISyntaxException;

public class Main {
    public static void main(String[] args) {
        try {
            String url = "https://www.example.com";
            String name = "John";
            int age = 25;
            URI uri = new URI(url);
            String query = uri.getQuery(); // 获取原始查询参数
            String newQuery = (query == null) ? "" : query + "&";
            newQuery += "name=" + name + "&age=" + age; // 添加新的查询参数
            URI newUri = new URI(uri.getScheme(), uri.getAuthority(), uri.getPath(), newQuery, uri.getFragment());
            String fullUrl = newUri.toString();
        } catch (URISyntaxException e) {
            e.printStackTrace();
        }
    }
}

import org.apache.http.client.utils.URIBuilder;
import java.net.URI;
import java.net.URISyntaxException;

public class Main {
    public static void main(String[] args) {
        try {
            String url = "https://www.example.com";
            String name = "John";
            int age = 25;
            URIBuilder builder = new URIBuilder(url);
            builder.addParameter("name", name); // 添加查询参数name
            builder.addParameter("age", Integer.toString(age)); // 添加查询参数age
            URI uri = builder.build();
            String fullUrl = uri.toString();
        } catch (URISyntaxException e) {
            e.printStackTrace();
        }
    }
}