如何在集合上反序列化具有递增ID的XML？

import org.w3c.dom.*;
import javax.xml.parsers.*;
import java.io.*;

public class XMLDeserializer {
    public static void main(String[] args) {
        try {
            // 创建DOM解析器工厂
            DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
            DocumentBuilder builder = factory.newDocumentBuilder();

            // 读取XML文件
            Document document = builder.parse(new File("data.xml"));

            // 获取根元素
            Element root = document.getDocumentElement();

            // 遍历子元素
            NodeList nodeList = root.getChildNodes();
            for (int i = 0; i < nodeList.getLength(); i++) {
                Node node = nodeList.item(i);
                if (node.getNodeType() == Node.ELEMENT_NODE) {
                    Element element = (Element) node;

                    // 解析元素属性
                    int id = Integer.parseInt(element.getAttribute("id"));
                    String name = element.getAttribute("name");

                    // 创建数据模型对象
                    DataModel dataModel = new DataModel(id, name);

                    // 将对象添加到集合中
                    // 这里使用List作为示例
                    dataList.add(dataModel);
                }
            }

            // 打印集合中的数据
            for (DataModel dataModel : dataList) {
                System.out.println(dataModel.getId() + ": " + dataModel.getName());
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

class DataModel {
    private int id;
    private String name;

    public DataModel(int id, String name) {
        this.id = id;
        this.name = name;
    }

    public int getId() {
        return id;
    }

    public String getName() {
        return name;
    }
}