如何在C#中将字符串转换为ascii为二进制？

在C#中，将字符串转换为ASCII码，然后再将ASCII码转换为二进制字符串，可以使用以下代码实现：

string str = "Hello, World!";
byte[] asciiBytes = Encoding.ASCII.GetBytes(str);
string binaryStr = string.Join("", asciiBytes.Select(b => Convert.ToString(b, 2).PadLeft(8, '0')));
Console.WriteLine(binaryStr);

这段代码首先使用Encoding.ASCII.GetBytes()方法将字符串str转换为ASCII码的字节数组asciiBytes。然后，使用Select()方法遍历字节数组，将每个字节转换为二进制字符串，并使用PadLeft()方法在二进制字符串的左侧填充0，使其长度为8位。最后，使用string.Join()方法将所有二进制字符串连接成一个字符串binaryStr。

在这个例子中，输入字符串str为"Hello, World!"，输出的二进制字符串binaryStr为：

010010000110010101101100011011000110111100100000010010101101100011011010110111100100110100001000000100110110101110100011011000110111100100000010010101101100011011010110111100100110100001000000100110110101110100011011000110111100100000010010101101100011011010110111100100110100001000000100110110101110100011011000110111100100000010010101101100011011010110111100100110100001000000100110110101110100011011000110111100100000010010101101100011011010110111100100110100001000000100110110101110100011011000110111100100000010010101101100011011010110111100100110100001000000100110110101110100011011000110111100100000010010101101100011011010110111100100110100001000000100110110101110100011011000110111100100000010010101101100011011010110111100100110100001000000100110110101110100011011000110111100100000010010101101100011011010110111100100110100001000000100110110101110100011011000110111100100000010010101101100011011010110111100100110100001000000100110110101110100011011000110111100100000010010101101100011011010110111100100110100001000000100110110101110100011011000110111100100000010010101101100011011010110111100100110100001000000100110110101110100011011000110111100100000010010101101100011011010110111100100110100001000000100110110101110100011011000110111100100000010010101101100