如何在C#窗体中用相同Id连接两个不同数据库的MS access表

OleDbConnection conn1 = new OleDbConnection();
OleDbConnection conn2 = new OleDbConnection();

string connString1 = @"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=C:\path\to\database1.accdb;Persist Security Info=False;";
string connString2 = @"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=C:\path\to\database2.accdb;Persist Security Info=False;";

conn1.ConnectionString = connString1;
conn2.ConnectionString = connString2;

conn1.Open();
conn2.Open();

OleDbCommand cmd1 = new OleDbCommand("SELECT * FROM table1", conn1);
OleDbCommand cmd2 = new OleDbCommand("SELECT * FROM table2", conn2);

// 执行查询并获取结果
OleDbDataReader reader1 = cmd1.ExecuteReader();
while (reader1.Read())
{
    // 处理结果
}

// 执行查询并获取结果
OleDbDataReader reader2 = cmd2.ExecuteReader();
while (reader2.Read())
{
    // 处理结果
}

reader1.Close();
reader2.Close();
conn1.Close();
conn2.Close();