如何在C#Zip中组合两个以上的通用列表？

using System.IO;
using ICSharpCode.SharpZipLib.Core;
using ICSharpCode.SharpZipLib.Zip;

// 假设这两个列表分别包含文件路径和文件名
List<string> filePaths = new List<string> {
    "path/to/file1.txt",
    "path/to/file2.txt",
    "path/to/file3.txt"
};
List<string> fileNames = new List<string> {
    "file1.txt",
    "file2.txt",
    "file3.txt"
};

// 将两个列表组合成一个新的ZipArchiveData<T>对象
ZipArchiveData<string> zipData = new ZipArchiveData<string>();
zipData.Name = "combined_files.zip";

foreach (string filePath in filePaths) {
    ZipArchiveEntry entry = zipData.AddFile(filePath);
    entry.Comment = "File: " + fileNames[filePaths.IndexOf(filePath)];
}

// 将ZipArchiveData<T>对象写入文件
using (FileStream zipFileStream = new FileStream("combined_files.zip", FileMode.Create, FileAccess.Write, FileShare.Write)) {
    zipData.SaveData(zipFileStream);
}