如何在FluentAssertions集合断言中重用自定义对象断言

public static class CustomAssertions
{
    public static AndConstraint<GenericCollectionAssertions<T>> ContainCustomObject<T>(
        this GenericCollectionAssertions<T> collectionAssertions, CustomObject expectedObject)
    {
        // 自定义断言逻辑
        // 使用 FluentAssertions 提供的方法进行断言
        collectionAssertions.Should().Contain(item => item.Property1 == expectedObject.Property1
                                                    && item.Property2 == expectedObject.Property2
                                                    && item.Property3 == expectedObject.Property3);

        return new AndConstraint<GenericCollectionAssertions<T>>(collectionAssertions);
    }
}

[Test]
public void TestCustomObjectAssertion()
{
    // 假设有一个包含 CustomObject 的集合
    List<CustomObject> customObjects = new List<CustomObject>
    {
        new CustomObject { Property1 = "Value1", Property2 = "Value2", Property3 = "Value3" },
        new CustomObject { Property1 = "Value4", Property2 = "Value5", Property3 = "Value6" }
    };

    // 使用自定义扩展方法进行断言
    customObjects.Should().ContainCustomObject(new CustomObject { Property1 = "Value1", Property2 = "Value2", Property3 = "Value3" });
}