如何在JAVA中将JSON转换为指定的XML结构

import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.dataformat.xml.XmlMapper;

public class JsonToXmlConverter {
    public static void main(String[] args) {
        try {
            // JSON数据
            String json = "{\"name\":\"John\", \"age\":30, \"city\":\"New York\"}";

            // 创建ObjectMapper对象
            ObjectMapper objectMapper = new ObjectMapper();

            // 将JSON转换为JAVA对象
            MyObject myObject = objectMapper.readValue(json, MyObject.class);

            // 创建XmlMapper对象
            XmlMapper xmlMapper = new XmlMapper();

            // 将JAVA对象转换为XML
            String xml = xmlMapper.writeValueAsString(myObject);

            // 输出XML
            System.out.println(xml);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

class MyObject {
    private String name;
    private int age;
    private String city;

    // 省略getter和setter方法
}