如何在JAVA中获取根据用户选择而改变的JsonObjects？

import com.google.gson.Gson;
import com.google.gson.JsonObject;

public class Main {
    public static void main(String[] args) {
        // 创建一个Json对象
        JsonObject jsonObject = new JsonObject();

        // 假设用户选择了A选项
        String userChoice = "A";

        // 根据用户选择构建Json对象
        if (userChoice.equals("A")) {
            jsonObject.addProperty("option", "A");
            jsonObject.addProperty("description", "Option A is selected.");
        } else if (userChoice.equals("B")) {
            jsonObject.addProperty("option", "B");
            jsonObject.addProperty("description", "Option B is selected.");
        } else {
            jsonObject.addProperty("option", "Unknown");
            jsonObject.addProperty("description", "Unknown option is selected.");
        }

        // 将Json对象转换为字符串
        Gson gson = new Gson();
        String jsonString = gson.toJson(jsonObject);

        System.out.println(jsonString);
    }
}