如何在Java中将Badgerfish风格的JSON转换为XML？

import com.fasterxml.jackson.core.JsonFactory;
import com.fasterxml.jackson.core.JsonParser;
import com.fasterxml.jackson.core.JsonToken;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.SerializationFeature;
import com.fasterxml.jackson.dataformat.xml.XmlMapper;

import java.io.IOException;

public class BadgerfishJsonToXmlConverter {

    public static void main(String[] args) throws IOException {
        // Badgerfish风格的JSON字符串
        String json = "{\"root\":{\"@xmlns\":{\"$\":\"http://example.com\"},\"name\":{\"$\":\"John\"},\"age\":{\"$\":30}}}";

        // 创建JsonFactory和JsonParser
        JsonFactory jsonFactory = new JsonFactory();
        JsonParser jsonParser = jsonFactory.createParser(json);

        // 创建XmlMapper
        XmlMapper xmlMapper = new XmlMapper();
        xmlMapper.enable(SerializationFeature.INDENT_OUTPUT);

        // 解析JSON并转换为XML
        JsonToken token;
        while ((token = jsonParser.nextToken()) != null) {
            if (token == JsonToken.START_OBJECT) {
                xmlMapper.writeStartObject();
            } else if (token == JsonToken.END_OBJECT) {
                xmlMapper.writeEndObject();
            } else if (token == JsonToken.FIELD_NAME) {
                String fieldName = jsonParser.getCurrentName();
                xmlMapper.writeFieldName(fieldName);
            } else if (token == JsonToken.VALUE_STRING) {
                String value = jsonParser.getValueAsString();
                xmlMapper.writeString(value);
            }
        }

        // 输出转换后的XML
        String xml = xmlMapper.writeValueAsString(xmlMapper.getNodeFactory().getCodec().readTree(jsonParser));
        System.out.println(xml);
    }
}