如何在Java语言中从arraylist api响应中检索jsonObjects

import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;

import java.util.ArrayList;
import java.util.Iterator;

public class RetrieveJSONObjects {
    public static void main(String[] args) {
        // 示例API响应
        String apiResponse = "[{\"name\":\"John\",\"age\":30},{\"name\":\"Jane\",\"age\":25}]";

        // 解析JSON数组
        JSONParser parser = new JSONParser();
        try {
            JSONArray jsonArray = (JSONArray) parser.parse(apiResponse);

            // 遍历JSON数组
            Iterator<JSONObject> iterator = jsonArray.iterator();
            while (iterator.hasNext()) {
                JSONObject jsonObject = iterator.next();

                // 检索JSON对象中的属性
                String name = (String) jsonObject.get("name");
                long age = (Long) jsonObject.get("age");

                // 打印结果
                System.out.println("Name: " + name);
                System.out.println("Age: " + age);
            }
        } catch (ParseException e) {
            e.printStackTrace();
        }
    }
}