如何在JavaScript中动态地将对象排除在链表之外？

class ListNode {
  constructor(data) {
    this.data = data;
    this.next = null;
  }
}

class LinkedList {
  constructor() {
    this.head = null;
  }

  // 添加节点到链表尾部
  append(data) {
    const newNode = new ListNode(data);
    if (!this.head) {
      this.head = newNode;
      return;
    }
    let current = this.head;
    while (current.next) {
      current = current.next;
    }
    current.next = newNode;
  }

  // 从链表中删除特定数据的节点
  remove(data) {
    if (!this.head) return;
    if (this.head.data === data) {
      this.head = this.head.next;
      return;
    }
    let current = this.head;
    while (current.next && current.next.data !== data) {
      current = current.next;
    }
    if (current.next) {
      current.next = current.next.next;
    }
  }

  // 打印链表中的所有数据
  printList() {
    let current = this.head;
    while (current) {
      console.log(current.data);
      current = current.next;
    }
  }
}

const list = new LinkedList();
list.append('A');
list.append('B');
list.append('C');

console.log('Original List:');
list.printList();

list.remove('B');

console.log('List after removing B:');
list.printList();