如何在NodeJS中同步2个异步函数？

function asyncFunc1(callback) {
  setTimeout(function() {
    callback(null, 'Result from asyncFunc1');
  }, 1000);
}

function asyncFunc2(arg, callback) {
  setTimeout(function() {
    callback(null, 'Result from asyncFunc2 using ' + arg);
  }, 1000);
}

asyncFunc1(function(err, result1) {
  if (err) {
    console.error(err);
    return;
  }
  
  asyncFunc2(result1, function(err, result2) {
    if (err) {
      console.error(err);
      return;
    }
    
    console.log(result2);
  });
});

function asyncFunc1() {
  return new Promise(function(resolve, reject) {
    setTimeout(function() {
      resolve('Result from asyncFunc1');
    }, 1000);
  });
}

function asyncFunc2(arg) {
  return new Promise(function(resolve, reject) {
    setTimeout(function() {
      resolve('Result from asyncFunc2 using ' + arg);
    }, 1000);
  });
}

asyncFunc1()
  .then(function(result1) {
    return asyncFunc2(result1);
  })
  .then(function(result2) {
    console.log(result2);
  })
  .catch(function(err) {
    console.error(err);
  });

function asyncFunc1() {
  return new Promise(function(resolve, reject) {
    setTimeout(function() {
      resolve('Result from asyncFunc1');
    }, 1000);
  });
}

function asyncFunc2(arg) {
  return new Promise(function(resolve, reject) {
    setTimeout(function() {
      resolve('Result from asyncFunc2 using ' + arg);
    }, 1000);
  });
}

async function main() {
  try {
    const result1 = await asyncFunc1();
    const result2 = await asyncFunc2(result1);
    console.log(result2);
  } catch (err) {
    console.error(err);
  }
}

main();