如何在Scala中将嵌套的json对象的一部分作为字符串读取

libraryDependencies += "com.typesafe.play" %% "play-json" % "2.9.2"

import play.api.libs.json._

val json = Json.parse("""
  {
    "name": "John",
    "age": 30,
    "address": {
      "street": "123 Main St",
      "city": "New York"
    }
  }
""")

val addressPath = JsPath \ "address"

val addressString = (json \ addressPath).as[String]

import play.api.libs.json._

val json = Json.parse("""
  {
    "name": "John",
    "age": 30,
    "address": {
      "street": "123 Main St",
      "city": "New York"
    }
  }
""")

val addressPath = JsPath \ "address"
val addressString = (json \ addressPath).as[String]

println(addressString)