如何在Scala中捕获进程的输出

import scala.sys.process._

object ProcessOutputCapture {
  def main(args: Array[String]): Unit = {
    val command = "ls"
    val process = Process(command)
    val output = process.lineStream_!

    output.foreach(println)
  }
}

import scala.sys.process._

object ProcessOutputCapture {
  def main(args: Array[String]): Unit = {
    val command = "ls"
    val process = Process(command)
    val output = new StringBuilder
    val error = new StringBuilder

    val logger = ProcessLogger(
      line => output.append(line + "\n"),
      line => error.append(line + "\n")
    )

    val exitCode = process.run(logger).exitValue()

    println("Output:")
    println(output.toString())

    println("Error:")
    println(error.toString())

    println("Exit code: " + exitCode)
  }
}