如何在Sequelize中使用Case条件？

const { Sequelize, Op } = require('sequelize');
const sequelize = new Sequelize('sqlite::memory:'); // 示例使用SQLite内存数据库

// 定义一个模型
const User = sequelize.define('User', {
  name: Sequelize.STRING,
  age: Sequelize.INTEGER
});

// 同步模型到数据库
sequelize.sync();

// 使用Simple Case条件
const usersWithAgeLabel = await User.findAll({
  attributes: [
    'id',
    'name',
    [Sequelize.fn('CASE WHEN', Sequelize.col('age'), '<', 18, 'THEN', 'Minor', 'ELSE', 'Adult', 'END'), 'ageLabel']
  ]
});

console.log(usersWithAgeLabel);

// 使用Searched Case条件
const usersWithComplexLabel = await User.findAll({
  attributes: [
    'id',
    'name',
    [Sequelize.fn('CASE WHEN', Sequelize.col('age'), '<', 18, 'THEN', 'Minor',
      'WHEN', Sequelize.col('age'), 'BETWEEN', 18, 65, 'THEN', 'Adult',
      'ELSE', 'Senior', 'END'), 'ageGroup']
  ]
});

console.log(usersWithComplexLabel);