如何在TypeScript中声明带有属性的函数的类型？

interface MyFunction {
  (param1: string, param2: number): boolean;
  myProperty: string;
}

const myFunc: MyFunction = (param1, param2) => {
  // 函数体
  return true;
};

myFunc.myProperty = "example";

console.log(myFunc("hello", 42)); // 输出: true
console.log(myFunc.myProperty); // 输出: example

type MyFunction = {
  (param1: string, param2: number): boolean;
  myProperty: string;
};

const myFunc: MyFunction = (param1, param2) => {
  // 函数体
  return true;
};

myFunc.myProperty = "example";

console.log(myFunc("hello", 42)); // 输出: true
console.log(myFunc.myProperty); // 输出: example