如何在android中以Toast的形式直接从httpclient获取特定响应，而不显示在链接中

android {
    // ...
    useLibrary 'org.apache.http.legacy'
}

import android.os.AsyncTask;
import android.widget.Toast;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;

public class HttpTask extends AsyncTask<String, Void, String> {
    @Override
    protected String doInBackground(String... urls) {
        String response = null;
        try {
            HttpClient httpClient = new DefaultHttpClient();
            HttpGet httpGet = new HttpGet(urls[0]);
            HttpResponse httpResponse = httpClient.execute(httpGet);
            response = EntityUtils.toString(httpResponse.getEntity());
        } catch (Exception e) {
            e.printStackTrace();
        }
        return response;
    }

    @Override
    protected void onPostExecute(String response) {
        if (response != null) {
            Toast.makeText(getApplicationContext(), response, Toast.LENGTH_SHORT).show();
        } else {
            Toast.makeText(getApplicationContext(), "Failed to get response", Toast.LENGTH_SHORT).show();
        }
    }
}

Button button = findViewById(R.id.button);
button.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
        String url = "http://example.com/api/endpoint";
        new HttpTask().execute(url);
    }
});