如何在android中使用Firebase动态链接获取短URL链接？

implementation 'com.google.firebase:firebase-dynamic-links:20.1.0'

FirebaseDynamicLinks.getInstance().getDynamicLink(getIntent())
    .addOnSuccessListener(this, new OnSuccessListener<PendingDynamicLinkData>() {
        @Override
        public void onSuccess(PendingDynamicLinkData pendingDynamicLinkData) {
            // 处理获取到的动态链接数据
            if (pendingDynamicLinkData != null) {
                Uri deepLink = pendingDynamicLinkData.getLink();
                // 在这里处理深度链接
            }
        }
    })
    .addOnFailureListener(this, new OnFailureListener() {
        @Override
        public void onFailure(@NonNull Exception e) {
            // 处理获取动态链接失败的情况
        }
    });

FirebaseDynamicLinks.getInstance().createDynamicLink()
    .setLink(Uri.parse("https://example.com/"))
    .setDomainUriPrefix("https://your-domain.page.link")
    .setAndroidParameters(new DynamicLink.AndroidParameters.Builder().build())
    .buildShortDynamicLink()
    .addOnSuccessListener(new OnSuccessListener<ShortDynamicLink>() {
        @Override
        public void onSuccess(ShortDynamicLink shortDynamicLink) {
            // 获取到短URL链接
            Uri shortLink = shortDynamicLink.getShortLink();
            // 在这里使用短URL链接
        }
    })
    .addOnFailureListener(new OnFailureListener() {
        @Override
        public void onFailure(@NonNull Exception e) {
            // 处理创建动态链接失败的情况
        }
    });