如何在discord.py中为不一致音乐机器人创建跳过命令？

import discord
from discord.ext import commands

bot = commands.Bot(command_prefix='!')

@bot.command()
async def skip(ctx):
    voice_channel = ctx.message.author.voice.channel
    voice_client = discord.utils.get(bot.voice_clients, guild=ctx.guild)
    
    if voice_client and voice_client.is_playing():
        voice_client.stop()
        await ctx.send("已跳过当前音乐")
    else:
        await ctx.send("当前没有正在播放的音乐")

bot.run('YOUR_BOT_TOKEN')