如何在nodejs中一个接一个地发送请求

const http = require('http');

function makeRequest(url, callback) {
  http.get(url, (res) => {
    let data = '';
    res.on('data', (chunk) => {
      data += chunk;
    });
    res.on('end', () => {
      callback(null, data);
    });
  }).on('error', (err) => {
    callback(err);
  });
}

function requestInSequence(urls, finalCallback) {
  let results = [];
  let index = 0;

  function handleResult(err, data) {
    if (err) return finalCallback(err);
    results.push(data);
    index++;
    if (index === urls.length) {
      finalCallback(null, results);
    } else {
      makeRequest(urls[index], handleResult);
    }
  }

  makeRequest(urls[index], handleResult);
}

const urls = [
  'http://example.com',
  'http://example.org',
  'http://example.net'
];

requestInSequence(urls, (err, results) => {
  if (err) {
    console.error('Error:', err);
  } else {
    console.log('Results:', results);
  }
});

const axios = require('axios');

async function makeRequest(url) {
  try {
    const response = await axios.get(url);
    return response.data;
  } catch (error) {
    throw error;
  }
}

async function requestInSequence(urls) {
  const results = [];
  for (const url of urls) {
    try {
      const data = await makeRequest(url);
      results.push(data);
    } catch (error) {
      console.error(`Error fetching ${url}:`, error.message);
    }
  }
  return results;
}

const urls = [
  'http://example.com',
  'http://example.org',
  'http://example.net'
];

requestInSequence(urls).then(results => {
  console.log('Results:', results);
}).catch(error => {
  console.error('Error:', error);
});