如何在php中传递创建表的外键

CREATE TABLE table1 (
    id INT PRIMARY KEY,
    name VARCHAR(50)
);

CREATE TABLE table2 (
    id INT PRIMARY KEY,
    table1_id INT,
    FOREIGN KEY (table1_id) REFERENCES table1(id)
);

$servername = "localhost";
$username = "your_username";
$password = "your_password";
$dbname = "your_database";

// 创建数据库连接
$conn = new mysqli($servername, $username, $password, $dbname);

// 检查连接是否成功
if ($conn->connect_error) {
    die("连接失败: " . $conn->connect_error);
}

// 执行SQL语句
$sql1 = "CREATE TABLE table1 (
    id INT PRIMARY KEY,
    name VARCHAR(50)
)";

$sql2 = "CREATE TABLE table2 (
    id INT PRIMARY KEY,
    table1_id INT,
    FOREIGN KEY (table1_id) REFERENCES table1(id)
)";

if ($conn->query($sql1) === TRUE && $conn->query($sql2) === TRUE) {
    echo "表和外键创建成功";
} else {
    echo "创建表和外键时出错: " . $conn->error;
}

// 关闭数据库连接
$conn->close();