如何在python中自定义日历年数据的时间(半月和10天)拆分？

import datetime

def custom_calendar(year):
    start_date = datetime.date(year, 1, 1)  # 指定起始日期
    end_date = datetime.date(year+1, 1, 1)  # 指定结束日期，为下一年的第一天

    calendar = []
    current_date = start_date

    while current_date < end_date:
        if current_date.day <= 10:
            interval = 10  # 按照10天进行拆分
        else:
            interval = 15  # 按照半月进行拆分

        next_date = current_date + datetime.timedelta(days=interval)
        calendar.append((current_date, next_date))

        current_date = next_date

    return calendar

# 调用函数并打印结果
year = 2022  # 指定年份
calendar = custom_calendar(year)
for interval in calendar:
    print(interval)