如何在python中获取列的n个最小值对应的日期时间索引

import pandas as pd

df = pd.DataFrame({'date': ['2022-01-01', '2022-01-02', '2022-01-03', '2022-01-04'],
                   'value': [10, 5, 8, 3]})
df['date'] = pd.to_datetime(df['date'])
df.set_index('date', inplace=True)

n = 2  # 获取2个最小值对应的日期时间索引
smallest_indices = df['value'].nsmallest(n).index