如何在python3中将相同的键赋给列表中的所有值

keys = ['a', 'b', 'c']
value = 10

# 使用字典推导式创建字典
my_dict = {key: value for key in keys}
print(my_dict)
# 输出: {'a': 10, 'b': 10, 'c': 10}

keys = ['a', 'b', 'c']
value = 10
my_dict = {}

# 使用循环为每个键赋相同的值
for key in keys:
    my_dict[key] = value

print(my_dict)
# 输出: {'a': 10, 'b': 10, 'c': 10}

keys = ['a', 'b', 'c']
value = 10

# 使用fromkeys()方法创建字典
my_dict = dict.fromkeys(keys, value)
print(my_dict)
# 输出: {'a': 10, 'b': 10, 'c': 10}

# 键列表中有重复
keys = ['a', 'b', 'a']
value = 10

# 使用字典推导式创建字典
my_dict = {key: value for key in keys}
print(my_dict)
# 输出: {'a': 10, 'b': 10}  # 注意键'a'只出现一次

keys = ['a', 'b', 'a']
value = 10

# 使用defaultdict来处理重复键
from collections import defaultdict
my_dict = defaultdict(list)
for key in keys:
    my_dict[key].append(value)

print(dict(my_dict))
# 输出: {'a': [10, 10], 'b': [10]}  # 所有键值对都被保留