如何在std::index_sequence上迭代

#include <iostream>

// 递归终止条件，当index_sequence为空时停止迭代
template <typename Func, typename... Args>
void iterate_index_sequence(Func&& func, std::index_sequence<>, Args&&... args) {
    // do nothing
}

// 递归迭代index_sequence，每次迭代调用func，并将当前索引和参数传递给func
template <std::size_t I, std::size_t... Is, typename Func, typename... Args>
void iterate_index_sequence(Func&& func, std::index_sequence<I, Is...>, Args&&... args) {
    func(std::integral_constant<std::size_t, I>{}, std::forward<Args>(args)...);
    iterate_index_sequence(std::forward<Func>(func), std::index_sequence<Is...>{}, std::forward<Args>(args)...);
}

// 示例函数，用于打印索引和参数
template <typename Index, typename... Args>
void print_index_and_args(Index index, Args&&... args) {
    std::cout << "Index: " << index << ", Args: ";
    ((std::cout << args << " "), ...);
    std::cout << std::endl;
}

int main() {
    iterate_index_sequence(print_index_and_args<int, char, float>, std::index_sequence<0, 1, 2>{}, 42, 'a', 3.14f);
    return 0;
}

Index: 0, Args: 42 a 3.14 
Index: 1, Args: 42 a 3.14 
Index: 2, Args: 42 a 3.14