如何在swift中将参数传递给post API

guard let url = URL(string: "https://example.com/api") else {
    print("Invalid URL")
    return
}

var request = URLRequest(url: url)
request.httpMethod = "POST"
request.setValue("application/json", forHTTPHeaderField: "Content-Type")

let parameters = ["key1": "value1", "key2": "value2"]
do {
    request.httpBody = try JSONSerialization.data(withJSONObject: parameters, options: [])
} catch {
    print("Error serializing parameters: \(error)")
    return
}

let task = URLSession.shared.dataTask(with: request) { (data, response, error) in
    if let error = error {
        print("Error: \(error)")
        return
    }
    
    if let data = data {
        // 处理响应数据
        do {
            let json = try JSONSerialization.jsonObject(with: data, options: [])
            print("Response: \(json)")
        } catch {
            print("Error deserializing response: \(error)")
        }
    }
}

task.resume()