如何在typescript中声明方法链接的递归类型？

type RecursiveMethod<T> = T & {
  next?: RecursiveMethod<T>;
};

interface MyObject {
  name: string;
  age: number;
}

const obj1: RecursiveMethod<MyObject> = {
  name: "John",
  age: 25,
  next: {
    name: "Jane",
    age: 30,
    next: {
      name: "Bob",
      age: 40,
    },
  },
};

console.log(obj1.name); // 输出 "John"
console.log(obj1.next?.name); // 输出 "Jane"
console.log(obj1.next?.next?.name); // 输出 "Bob"