如何在typescript中获得严格类型的值？

let myNumber: number = 10;
function addNumbers(a: number, b: number): number {
  return a + b;
}

let myString = "Hello"; // 推断为string类型
let myArray = [1, 2, 3]; // 推断为number[]类型

interface Person {
  name: string;
  age: number;
}

type Point = {
  x: number;
  y: number;
};

let person: Person = { name: "John", age: 25 };
let point: Point = { x: 10, y: 20 };

function identity<T>(arg: T): T {
  return arg;
}

let result = identity<number>(10); // 指定泛型类型为number

let myValue: any = "Hello";
let myLength: number = (myValue as string).length;