如何将函数(有自己的参数)作为参数传递到函数中？

void function1(int x) {
    printf("This is function1, parameter: %d\n", x);
}

void function2(void (*func)(int), int y) {
    printf("This is function2\n");
    func(y);
}

int main() {
    function2(function1, 10);
    return 0;
}

#include <iostream>

class Function1 {
public:
    void operator()(int x) {
        std::cout << "This is function1, parameter: " << x << std::endl;
    }
};

void function2(Function1 func, int y) {
    std::cout << "This is function2" << std::endl;
    func(y);
}

int main() {
    Function1 func1;
    function2(func1, 10);
    return 0;
}

#include <iostream>

void function2(void (*func)(int), int y) {
    std::cout << "This is function2" << std::endl;
    func(y);
}

int main() {
    int x = 10;
    function2([x](int y) {
        std::cout << "This is lambda function, parameter: " << y << ", captured variable: " << x << std::endl;
    }, 20);
    return 0;
}