如何将列表组合成一个字典，其中嵌套列表的第一个元素是键

def list_to_dict(lst):
    result = {}
    for sublist in lst:
        key = sublist[0]
        value = sublist[1:]
        result[key] = value
    return result

# 示例使用
my_list = [['key1', 'value1'], ['key2', 'value2'], ['key3', 'value3']]
my_dict = list_to_dict(my_list)
print(my_dict)

{'key1': ['value1'], 'key2': ['value2'], 'key3': ['value3']}