如何将对象节点的Json数组解析为不同的dto对象

import com.fasterxml.jackson.databind.ObjectMapper;

// 定义DTO类
class UserDTO {
    private String name;
    private int age;

    // 构造函数
    public UserDTO(String name, int age) {
        this.name = name;
        this.age = age;
    }

    // Getter和Setter方法
    // ...

    @Override
    public String toString() {
        return "UserDTO [name=" + name + ", age=" + age + "]";
    }
}

class ProductDTO {
    private String name;
    private double price;

    // 构造函数
    public ProductDTO(String name, double price) {
        this.name = name;
        this.price = price;
    }

    // Getter和Setter方法
    // ...

    @Override
    public String toString() {
        return "ProductDTO [name=" + name + ", price=" + price + "]";
    }
}

public class JsonArrayToDtoExample {
    public static void main(String[] args) {
        // 模拟Json数组
        String jsonArray = "[{\"type\":\"user\",\"name\":\"John\",\"age\":25},{\"type\":\"product\",\"name\":\"Phone\",\"price\":999.99}]";

        try {
            // 创建ObjectMapper对象
            ObjectMapper objectMapper = new ObjectMapper();

            // 解析Json数组为对象数组
            Object[] objects = objectMapper.readValue(jsonArray, Object[].class);

            // 遍历对象数组
            for (Object obj : objects) {
                // 将Json对象转换为对应的DTO对象
                if (obj instanceof java.util.LinkedHashMap) {
                    java.util.LinkedHashMap<String, Object> jsonMap = (java.util.LinkedHashMap<String, Object>) obj;
                    String type = (String) jsonMap.get("type");

                    if ("user".equals(type)) {
                        UserDTO userDTO = new UserDTO((String) jsonMap.get("name"), (int) jsonMap.get("age"));
                        System.out.println(userDTO);
                    } else if ("product".equals(type)) {
                        ProductDTO productDTO = new ProductDTO((String) jsonMap.get("name"), (double) jsonMap.get("price"));
                        System.out.println(productDTO);
                    }
                }
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}