如何将按第一个元素排序的元组列表分组为包含重叠和非重叠元组的两个列表

def group_tuples(tuples):
    sorted_tuples = sorted(tuples, key=lambda x: x[0])
    overlapping_tuples = []
    non_overlapping_tuples = []

    for i in range(len(sorted_tuples)):
        if i > 0 and sorted_tuples[i][0] == sorted_tuples[i-1][0]:
            overlapping_tuples.append(sorted_tuples[i])
        else:
            non_overlapping_tuples.append(sorted_tuples[i])

    return overlapping_tuples, non_overlapping_tuples

tuples = [(1, 'a'), (2, 'b'), (2, 'c'), (3, 'd'), (3, 'e'), (4, 'f')]
overlapping, non_overlapping = group_tuples(tuples)

print("Overlapping tuples:", overlapping)
print("Non-overlapping tuples:", non_overlapping)

Overlapping tuples: [(2, 'b'), (2, 'c'), (3, 'd'), (3, 'e')]
Non-overlapping tuples: [(1, 'a'), (4, 'f')]