如何将EventRecord xml转换为字典包括所有参数- C#

using System;
using System.Collections.Generic;
using System.Xml;

public class EventRecordConverter
{
    public static Dictionary<string, string> ConvertXmlToDictionary(string xml)
    {
        XmlDocument xmlDoc = new XmlDocument();
        xmlDoc.LoadXml(xml);

        Dictionary<string, string> dictionary = new Dictionary<string, string>();

        XmlNodeList nodes = xmlDoc.DocumentElement.ChildNodes;
        foreach (XmlNode node in nodes)
        {
            if (node.NodeType == XmlNodeType.Element)
            {
                string key = node.Name;
                string value = node.InnerText;
                dictionary.Add(key, value);
            }
        }

        return dictionary;
    }
}

public class Program
{
    public static void Main(string[] args)
    {
        string xml = "<EventRecord><EventID>123</EventID><Level>Information</Level><Message>Event message</Message></EventRecord>";

        Dictionary<string, string> dictionary = EventRecordConverter.ConvertXmlToDictionary(xml);

        foreach (KeyValuePair<string, string> kvp in dictionary)
        {
            Console.WriteLine("Key: " + kvp.Key);
            Console.WriteLine("Value: " + kvp.Value);
            Console.WriteLine();
        }
    }
}